Khan Academy
SAT Prep: Test 2 Section 9 Part 4
Price increases in real life aren't enjoyable, but Sal's enthusiasm and easygoing explanation makes the question on increasing prices on the practice SAT fun! Showing students how to easily work through problems involving the Pythagorean...
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Solving Linear Systems by Graphing
Sal teaches how to use graphing as a tool, not a hindrance, in this helpful video. His lecture would make be a good resource for your algebra class, particularly as the focus shifts to graphing problems and linear systems.
Khan Academy
SAT Prep: Test 5 Section 7 Part 5
Geometry problems on the SAT are often the most difficult for students to solve, let alone master. Focusing on several geometry-related skills (as well a few algebra problems), Sal makes this lesson a valuable resource for viewers who...
Khan Academy
SAT Prep: Test 1 Section 6 Part 6
Reviewing the last two problems in the practice SAT (17-18), Sal explains the process behind each problem more thoroughly. This video would be especially helpful for students who experience difficulty in graphing or in accurately reading...
Khan Academy
SAT Prep: Test 1 Section 6 Part 1
Here, Sal begins section 6 on page 407 of The Official SAT Study Guide, focusing on problems 1-4 in this video. He clarifies that SAT questions are "tricky, but really fast" problems that shouldn't take a lot of time to solve. To prove...
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SAT Prep: Test 7 Section 8 Part 2
Continuing his SAT review session, Sal explores problems with slopes, linear equations, and congruent angles. He begins problem 10 (geometry) but finishes the problem in the next video.
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Graphing Inequalities
If your class struggles with graphing inequalities, or if your lecture could use some help from Sal, this video would be a great help. Sal's instruction is measured and patient, and viewers will walk away feeling more confident and...
Khan Academy
SAT Prep: Test 6 Section 3 Part 4
The strength of this video lies in Sal's ability to immediately translate word problems to equations - a skill that might allow many SAT takers to have a better chance at finding the correct answer. If students watch him practice this...
Khan Academy
SAT Prep: Test 8 Section 8 Part 2
One of Sal's greatest gifts to students in this SAT video series has been his demonstration of word problems. Because he writes out equations while simultaneously reading the information provided, he often arrives at the correct answer...
Khan Academy
SAT Prep: Test 7 Section 2 Part 3
The problems are getting a little more difficult in this video, which covers problems 13-16 on page 778, but Sal is still easy to understand. He demonstrates various strategies for solving algebraic expressions and problems involving...
Khan Academy
SAT Prep: Test 2 Section 9 Part 3
Carefully reading word problems is a skill that many students neglect due to time constraints or test anxiety, and Sal models how to do so in this video. Both algebra and geometry are featured in problems 10-12 of the practice SAT.
Khan Academy
SAT Prep: Test 2 Section 9 Part 2
Assisting students with test-taking strategies, especially easier ways to solve multiple choice problems, Sal solves problems 6-9 on page 488 of The Official SAT Study Guide. Skills such as adding angles and solving for integers are the...
Khan Academy
SAT Prep: Test 3 Section 2 Part 4
Finding perimeters and slopes is the focus of this video, which details ways to solve problems 15-17 on the practice SAT. Even students who are confident in their ability to pass the SAT would benefit from this additional review.
Khan Academy
Carboxlic Acid Tautomeriztion
Sal defines the similarity of the carbonyl group on aldehyde to the carboxylic acid. Next, he clarifies the presence of the extra OH group instead of the carbon chain or hydrogen. He then recaps the definitions and behaviors of acids.
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Naming Benzene Derivatives Introduction
Familiarize your class with the benzene derivative compounds. Some Sal will recommend memorizing, while others are mainly presented as practice for naming.
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Naming Alkenes Examples
Sal "expands his repertoire" and starts to demonstrates naming of long complicated alkene chains.
Khan Academy
Khan Academy: Momentum : Introduction to Momentum
A video showing that momentum is the product of mass and velocity. Video contains a simple example problem to show how to calculate. [9:17]
Khan Academy
Khan Academy: Momentum: Ice Skater Throws a Ball
See how the conservation of momentum principles can be applied to a problem of an ice skater throwing a ball. This video lecture gives step by step example. [6:00]
Khan Academy
Khan Academy: Impacts and Linear Momentum: 2 Dimensional Momentum Problem
Solve a collision of balls in two dimensions problem using the conservations of momentum in this video. Video gives a step-by-step explanation of how to solve the problem to figure out what direction and velocity the balls travel after...
Khan Academy
Khan Academy: Momentum: 2 Dimensional Momentum Problem Part 2
Solve a collision of balls in two dimensions using the conservations of momentum in this video. Video discusses how specifically to use trigonometry to solve the direction and velocity of the balls after the collision. [9:32]
Khan Academy
Khan Academy: Moments, Torque, and Angular Momentum: Introduction to Torque
Learn that a torque is applied when a force causes an object to rotate around an axis in this video. Video overviews net torque and how to determine if torque is positive or negative. [9:24]
Khan Academy
Khan Academy: Moments, Torque, and Angular Momentum: Moments
Solve problems by using the Law of Moments in this video. Understand that moments is essentially the same concept as torque as explained in this video. [14:13]
Khan Academy
Khan Academy: Moments, Torque, and Angular Momentum: Moments Part 2
Solve problems by using the Law of Moments in this video. Understand that moments is essentially the same concept as torque as explained in this video. [13:49]
Khan Academy
Khan Academy: Moments, Torque, and Angular Momentum: Angular Momentum
A video exploring angular momentum which is how much movement an object has when it's rotating in a circle. Look at how the equation for angular momentum is derived. [11:18]
